5[3(z+2)+4]+2z=67

Solution for 5[3(z+2)+4]+2z=67 equation:

Simplifying
5[3(z + 2) + 4] + 2z = 67

Reorder the terms:
5[3(2 + z) + 4] + 2z = 67
5[(2 * 3 + z * 3) + 4] + 2z = 67
5[(6 + 3z) + 4] + 2z = 67

Reorder the terms:
5[6 + 4 + 3z] + 2z = 67

Combine like terms: 6 + 4 = 10
5[10 + 3z] + 2z = 67
[10 * 5 + 3z * 5] + 2z = 67
[50 + 15z] + 2z = 67

Combine like terms: 15z + 2z = 17z
50 + 17z = 67

Solving
50 + 17z = 67

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-50' to each side of the equation.
50 + -50 + 17z = 67 + -50

Combine like terms: 50 + -50 = 0
0 + 17z = 67 + -50
17z = 67 + -50

Combine like terms: 67 + -50 = 17
17z = 17

Divide each side by '17'.
z = 1

Simplifying
z = 1